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x^2+8-3=-2x-3
We move all terms to the left:
x^2+8-3-(-2x-3)=0
We add all the numbers together, and all the variables
x^2-(-2x-3)+5=0
We get rid of parentheses
x^2+2x+3+5=0
We add all the numbers together, and all the variables
x^2+2x+8=0
a = 1; b = 2; c = +8;
Δ = b2-4ac
Δ = 22-4·1·8
Δ = -28
Delta is less than zero, so there is no solution for the equation
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